C String Library and String Copy Function – strcpy()

This is the correct code for strncpy
#include <stdio.h>
#include <string.h>
int main()
{
char str1[6] = "Hello";
char str2[5] = "";
strncpy(str2, str1, sizeof(str2) – 1);
printf("%s", str2);
return 0;
}
(OR)
#include <stdio.h>
#include <string.h>
int main()
{
char str1[6] = "Hello";
char str2[5];
strncpy(str2, str1, sizeof(str2));
str2[sizeof(str2)-1]='';
printf("%s", str2);
return 0;
}

Output for both the programs : Hell

What do you mean by prototype here. I saw in some previous videos too but din quite understand what is prototype. We're using only strcpy(destination,source) but the prototype consist more. What is prototype and what it is used for???

int ch;

for(ch='A';ch>='Z';ch++){

printf("%c",ch); }

return 0;

}
what will be the output

In the case of strncpy : (5:25)
If str2 is "Hell". As str2 is of size 4. then what about the string terminator?
shouldn't it be "Hel" only?

But sir why not use a for loop like this

char str1[6] = "Hello";
char str2[6];

for(int i = 0; i < sizeof(str1); ++i)
str2[i] = str1[i];

But anyways fantastic lessons:)

Thank you sir! This is really helpful.

char c=48;

int i, mask=01;

for(i=1; i<=5; i++)

{

printf("%c", c|mask);

mask = mask<<1;

}

anyone explain me output of this..plz help

#include<stdio.h>

#include<string.h>

int main()

{

char str[6]="hello";

char str1[0];

strcpy( str1,str);

printf("%s",str1);

}
but this code is exuted in my computer please help………….
output is hello

Great videos sir!
One kind request please complete this course as fast as possible.

Sir please make video series on Algorithm's

Please make vedio series on data structures and algorithms